| Indian Wells – Women's doubles | |
|---|---|
| 2019 Oracle Challenger Series – Indian Wells | |
| Champions | |
| Runners-up | |
| Score | 7–6(9–7), 6–4 |
Kristýna Plíšková and Evgeniya Rodina won the title, defeating defending champions Taylor Townsend and Yanina Wickmayer,[1] in the final, 7–6(9–7), 6–4.
Seeds
Fanny Stollár /
Heather Watson (first round)
Nao Hibino /
Oksana Kalashnikova (quarterfinals)
Olga Danilović /
Nadiia Kichenok (first round)
Sorana Cîrstea /
Sara Sorribes Tormo (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | 6 | 3 | [5] | ||||||||||||||||||||||||
| 3 | 6 | [10] | 6 | 3 | [11] | ||||||||||||||||||||||
| 1 | 4 | 3 | 6 | [13] | |||||||||||||||||||||||
| 6 | 6 | 5 | 3 | ||||||||||||||||||||||||
| 4 | 5 | 6 | [5] | 7 | 6 | ||||||||||||||||||||||
| 7 | 3 | [10] | 2 | 6 | [9] | ||||||||||||||||||||||
| 6 | 7 | 6 | 1 | [11] | |||||||||||||||||||||||
| 2 | 5 | 79 | 6 | ||||||||||||||||||||||||
| WC | 64 | 6 | [3] | 67 | 4 | ||||||||||||||||||||||
| 77 | 4 | [10] | 6 | 6 | |||||||||||||||||||||||
| 4 | 6 | [10] | 3 | 0 | |||||||||||||||||||||||
| 3 | 6 | 3 | [6] | 2 | 4 | ||||||||||||||||||||||
| 6 | 6 | 6 | 6 | ||||||||||||||||||||||||
| 4 | 0 | 6 | 6 | ||||||||||||||||||||||||
| 2 | 0 | 2 | 2 | 3 | |||||||||||||||||||||||
| 2 | 6 | 6 | |||||||||||||||||||||||||
References
- ↑ "Oracle Challenger Indian Wells: Yanina takes home 2nd doubles title of the year". yaninawickmayer.com., March 5, 2018
External Links
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