Doubles
2009 Copa Petrobras Bogotá
ChampionsColombia Alejandro Falla
Colombia Alejandro González
Runners-upArgentina Sebastián Decoud
Argentina Diego Álvarez
Score5–7, 6–4, [10–8]

Juan Sebastián Cabal and Alejandro Falla were the defending champions, but Cabal didn't start this year.
Falla partnered with Alejandro González and they won this tournament, after defeating Sebastián Decoud and Diego Álvarez 5–7, 6–4, [10–8] in the final.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Finals
ALT Germany A Begemann
Argentina N Todero
6 6  
  Uruguay M Felder
Colombia C Salamanca
1 4   ALT Germany A Begemann
Argentina N Todero
3 5  
WC France V Millot
Denmark K Pless
3 60     United States A Bogomolov Jr.
Canada P Polansky
6 7  
  United States A Bogomolov Jr.
Canada P Polansky
6 7     United States A Bogomolov Jr.
Canada P Polansky
4 6 [9]
3 Brazil F Ferreiro
Argentina S Roitman
w/o       Colombia A Falla
Colombia A González
6 3 [11]
  Chile P Capdeville
United States E Nunez
        Chile P Capdeville
United States E Nunez
w/o    
WC Colombia F Mantilla
Colombia M Quintero
1 1     Colombia A Falla
Colombia A González
     
  Colombia A Falla
Colombia A González
6 6     Colombia A Falla
Colombia A González
5 6 [10]
  Argentina D Álvarez
Argentina S Decoud
7 67 [10]   Argentina D Álvarez
Argentina S Decoud
7 4 [8]
  Spain C Poch-Gradin
Brazil M Torres
63 7 [6]   Argentina D Álvarez
Argentina S Decoud
6 6  
WC Colombia J S Gómez
Colombia S Serrano
4 3   4 Argentina B Dabul
Argentina E Schwank
3 4  
4 Argentina B Dabul
Argentina E Schwank
6 6     Argentina D Álvarez
Argentina S Decoud
7 4 [11]
  Argentina M Alund
Argentina F del Bonis
2 0   2 Mexico S González
United States T Rettenmaier
62 6 [9]
  Brazil R Mello
Brazil C Zampieri
6 6     Brazil R Mello
Brazil C Zampieri
1 2  
  Italy R Ghedin
Colombia S Giraldo
4 0   2 Mexico S González
United States T Rettenmaier
6 6  
2 Mexico S González
United States T Rettenmaier
6 6  

References

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