Doubles
2010 Mordovia Cup
Champions	Ilya Belyaev Michail Elgin
Runners-up	Denys Molchanov Artem Smirnov
Score	3–6, 7–6(6), [11–9]

Michail Elgin and Evgeny Kirillov were the defending champions, but they chose to not compete together.
Elgin partnered up with Ilya Belyaev and Kirillov teamed up with Andrey Kuznetsov. They met in the semifinal and Elgin/Belyaev won 6–3, 4–6, [10–1].
This pair defeated Denys Molchanov and Artem Smirnov in the final 3–6, 7–6(6), [11–9].

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Finals
	1	A Kedryuk D Matsukevich	65	5
		I Belyaev M Elgin	7	7					I Belyaev M Elgin
		C Gârd P-A Luncanu	2	6	[7]				I Cervantes-Huegun P Santos	w/o
		I Cervantes-Huegun P Santos	6	3	[10]											I Belyaev M Elgin	6	4	[10]
	4	M Inoyatov A Sitak	6	6												E Kirillov A Kuznetsov	3	6	[1]
	WC	A Manegin V Rudnev	3	2				4	M Inoyatov A Sitak	4	3
		S Krotiouk A Lobkov	67	1					E Kirillov A Kuznetsov	6	6
		E Kirillov A Kuznetsov	7	6																			I Belyaev M Elgin	3	7	[11]
	WC	I Rud R Tudoreanu	3	3																		2	D Molchanov A Smirnov	6	66	[9]
		E Donskoy K Kravchuk	6	6					E Donskoy K Kravchuk	6	6
		C Niland I Sergeyev	2	4				3	A Kumantsov D Savić	4	4
	3	A Kumantsov D Savić	6	6												E Donskoy K Kravchuk	4	4
		M Kukushkin V Reshetnikov	3	7	[10]										2	D Molchanov A Smirnov	6	6
		A Boje-Ordóñez G Olaso	6	5	[8]				M Kukushkin V Reshetnikov	3	1
	WC	A Bury K Harbatsiuk	6	3	[6]			2	D Molchanov A Smirnov	6	6
	2	D Molchanov A Smirnov	3	6	[10]

References

• Doubles Draw