Women's singles
2019 Burnie International
Champion	Belinda Woolcock
Runner-up	Paula Badosa Gibert
Score	7–6(7–3), 7–6(7–4)

Marta Kostyuk was the defending champion, but lost to Wang Xiyu in the second round.^[1]

Qualifier Belinda Woolcock won the title, defeating Paula Badosa Gibert in the final, 7–6^(7–3), 7–6^(7–4).

Seeds

Draw

Finals

	Semifinals							Final
	1	Sara Sorribes Tormo	4	1
	6	Paula Badosa Gibert	6	6
								6	Paula Badosa Gibert	63	64
								Q	Belinda Woolcock	77	77
	Q	Belinda Woolcock	6	1	6
		Ekaterine Gorgodze	3	6	3

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	S Sorribes Tormo	7	6
	Q	N Podoroska	5	1				1	S Sorribes Tormo	2	6	7
	Q	J Elie	1	1					K Swan	6	3	5
		K Swan	6	6											1	S Sorribes Tormo	6	6
	WC	Z Hives	77	6											7	G García Pérez	0	2
		E Rybakina	61	4				WC	Z Hives	7	2	65
		B Haddad Maia	1	4				7	G García Pérez	5	6	77
	7	G García Pérez	6	6																		1	S Sorribes Tormo	4	1
	3	M Kostyuk	6	6																		6	P Badosa Gibert	6	6
	Q	K-c Chang	3	4				3	M Kostyuk	4	1
		E Perez	6	3	5				Xiy Wang	6	6
		Xiy Wang	4	6	7											Xiy Wang	6	3	2
		G Taylor	2	0r											6	P Badosa Gibert	3	6	6
		I Bara	6	2					I Bara	0	77	2
	Q	G Da Silva-Fick	4	2				6	P Badosa Gibert	6	64	6
	6	P Badosa Gibert	6	6

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	8	V Tomova	6	7
		M Zanevska	4	5				8	V Tomova	4	6	4
	Q	B Woolcock	6	77				Q	B Woolcock	6	3	6
	WC	N Bains	3	63											Q	B Woolcock	6	6
	Q	A Bai	3	3											WC	L Cabrera	1	4
	WC	L Cabrera	6	6				WC	L Cabrera	6	2	77
	WC	D Aiava	6					WC	D Aiava	4	6	65
	4	F Stollár	5r																			Q	B Woolcock	6	1	6
	5	I Khromacheva	4	5																			E Gorgodze	3	6	3
		A Muhammad	6	7					A Muhammad	2	4
		E Gorgodze	6	3	6				E Gorgodze	6	6
		A Zaja	1	6	3											E Gorgodze	6	5	6
		J Fourlis	5	2												S Soler Espinosa	4	7	1
		S Soler Espinosa	7	6					S Soler Espinosa	7	3	6
		Ar Rodionova	6	7					Ar Rodionova	5	6	2
	2	N Hibino	3	5

References

• Main Draw