1932 United States presidential election in Rhode Island

November 8, 1932

Nominee Franklin D. Roosevelt Herbert Hoover Party Democratic Republican Home state New York California Running mate John Nance Garner Charles Curtis Electoral vote 4 0 Popular vote 146,604 115,266 Percentage 55.08% 43.31%

County Results Roosevelt   50-60% Hoover   50-60%

President before election Herbert Hoover Republican Elected President Franklin D. Roosevelt Democratic

Elections in Rhode Island
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The 1932 United States presidential election in Rhode Island took place on November 8, 1932, as part of the 1932 United States presidential election which was held throughout all contemporary 48 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Democratic nominee, Governor Franklin D. Roosevelt of New York, over Republican nominee, incumbent President Herbert Hoover of California. Roosevelt running mate was incumbent Speaker of the House John Nance Garner of Texas, while Hoover's running mate was incumbent Vice President Charles Curtis of Kansas.

Roosevelt won Rhode Island by a margin of 11.77%.

Results

See also

• United States presidential elections in Rhode Island

References