Singles
1973 World Championship Tennis Finals
ChampionUnited States Stan Smith
Runner-upUnited States Arthur Ashe
Score6–3, 6–3, 4–6, 6–4
Draw8
Seeds8

Ken Rosewall was the defending champion but lost in the semifinals to Arthur Ashe.

Stan Smith won the singles title of the 1973 World Championship Tennis Finals after a 6–3, 6–3, 4–6, 6–4 in the final against Ashe.[1][2]

Seeds

A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.

  1. United States Stan Smith (champion)
  2. United Kingdom Roger Taylor (quarterfinals)
  3. United States Marty Riessen (quarterfinals)
  4. Australia Rod Laver (semifinals)
  5. Australia Roy Emerson (quarterfinals)
  6. United States Arthur Ashe (final)
  7. Australia Ken Rosewall (semifinals)
  8. Australia John Alexander (quarterfinals)

Draw

Key

Quarterfinals Semifinals Final
                     
1 United States Stan Smith 6 6 6    
8 Australia John Alexander 4 2 1    
1 United States Stan Smith 4 6 77 7  
4 Australia Rod Laver 6 4 62 5  
4 Australia Rod Laver 7 6 7    
5 Australia Roy Emerson 5 2 5    
1 United States Stan Smith 6 6 4 6  
6 United States Arthur Ashe 3 3 6 4  
6 United States Arthur Ashe 77 4 7 3 6
3 United States Marty Riessen 63 6 5 6 1
6 United States Arthur Ashe 6 6 5 1 6
7 Australia Ken Rosewall 4 2 7 6 2
7 Australia Ken Rosewall 4 6 65 6 6
2 United Kingdom Roger Taylor 6 2 77 1 4

References

  1. ↑ Roy Mark (May 15, 1973). "Smith proves he's number one player". The Austin American – via Newspapers.com.
  2. ↑ John Barrett, ed. (1974). World of Tennis '74 : a BP and Commercial Union yearbook. London: Queen Anne Press. p. 174. ISBN 9780362001686.
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