Doubles
1991 Arizona Classic
Champions	Peanut Harper Cammy MacGregor
Runners-up	Sandy Collins Elna Reinach
Score	7–5, 3–6, 6–3
Draw	16 (1Q)
Seeds	4

Elise Burgin and Helen Kelesi were the defending champions, but Kelesi did not compete this year. Burgin teamed up with Carrie Cunningham and lost in the first round to Isabelle Demongeot and Patty Fendick.

Peanut Harper and Cammy MacGregor won the title by defeating Sandy Collins and Elna Reinach 7–5, 3–6, 6–3 in the final.^[1]

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	N Provis E Smylie	6	5	5
		R Hiraki F Labat	2	7	7				R Hiraki F Labat	64	65
	Q	D Graham K Po	68	6	7			Q	D Graham K Po	77	77
		A Henricksson S Stafford	710	4	5										Q	D Graham K Po	5	2
	4	ML Daniels L Gregory	6	6												P Harper Ca MacGregor	7	6
		N Arendt S McCarthy	3	1				4	ML Daniels L Gregory	2	4
		P Harper Ca MacGregor	6	6					P Harper Ca MacGregor	6	6
		J Emmons M Lindström	1	3																			P Harper Ca MacGregor	7	3	6
		Lisa Seemann P Thorén	4	4																		3	S Collins E Reinach	5	6	3
		A Frazier G Helgeson	6	6					A Frazier G Helgeson	3	3
		A Gooden K Habšudová	4	0				3	S Collins E Reinach	6	6
	3	S Collins E Reinach	6	6											3	S Collins E Reinach	6	6
		B Bowes M Werdel	3	6	6										2	I Demongeot P Fendick	2	3
		A Grossman L Harvey Wild	6	3	0				B Bowes M Werdel	4	4
		E Burgin C Cunningham	1	7	3			2	I Demongeot P Fendick	6	6
	2	I Demongeot P Fendick	6	5	6

References

External links

• Official results archive (ITF)
• Official results archive (WTA)