Singles
2019 Lale Cup
Champion	Vitalia Diatchenko
Runner-up	Ankita Raina
Score	6–4, 6–0

Sabina Sharipova was the defending champion, but lost in the first round to Jana Čepelová.

Vitalia Diatchenko won the title, defeating Ankita Raina in the final, 6–4, 6–0.^[1]

Seeds

Draw

Finals

	Semifinals							Final
	1	Vitalia Diatchenko	6	6
		Jana Čepelová	0	2
								1	Vitalia Diatchenko	6	6
								6	Ankita Raina	4	0
	6	Ankita Raina	6	711
	2	Marie Bouzková	4	69

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	V Diatchenko	6	6
		F Al-Nabhani	3	1				1	V Diatchenko	6	6
	Q	I Popovic	4	4					G Poznikhirenko	0	0
		G Poznikhirenko	6	6											1	V Diatchenko	6	6
	WC	İ Öz	2	5											8	R Șerban	0	2
		O Ianchuk	6	7					O Ianchuk	1	0r
		P Özgen	5	3				8	R Șerban	6	3
	8	R Șerban	7	6																		1	V Diatchenko	6	6
	3	S Sharipova	0	6	4																		J Čepelová	0	2
		J Čepelová	6	4	6				J Čepelová	6	3	6
	Q	I Kremen	4	65					I Shinikova	4	6	2
		I Shinikova	6	77												J Čepelová	7	6
	WC	Z Sönmez	62	3											5	V Grammatikopoulou	5	4
		B Cengiz	77	6					B Cengiz	4	1
		P Monova	6	1r				5	V Grammatikopoulou	6	6
	5	V Grammatikopoulou	4	3

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	6	A Raina	6	6
	WC	B Tokaç	1	0				6	A Raina	6	6
	Q	S Lansere	6	6				Q	S Lansere	4	1
		A Hesse	4	1											6	A Raina	6	4	[10]
		A Gasanova	1	3												Ç Büyükakçay	4	6	[6]
		Ç Büyükakçay	6	6					Ç Büyükakçay	6	6
		N Abduraimova	6	6					N Abduraimova	2	2
	4	E Rybakina	3	4																		6	A Raina	6	711
	7	G Minnen	77	6																		2	M Bouzková	4	69
	WC	İ Soylu	65	2				7	G Minnen	6	6
		O Doroshina	5	6	6				O Doroshina	2	2
	Q	A Vrljić	7	4	2										7	G Minnen	2	1
	Q	S Wagner	6	6											2	M Bouzková	6	6
	Q	I Shymanovich	2	4				Q	S Wagner	2	4
		B Štefková	2	1				2	M Bouzková	6	6
	2	M Bouzková	6	6

References

• Main Draw