Singles
2023 Cranbrook Tennis Classic
Champion	Steve Johnson
Runner-up	Mikhail Kukushkin
Score	6–4, 6–7(7–9), 7–6(7–4)

This was the first edition of the tournament.^[1]

Steve Johnson won the title after defeating Mikhail Kukushkin 6–4, 6–7^(7–9), 7–6^(7–4) in the final.

Seeds

Draw

Finals

	Semifinals							Final
		Tennys Sandgren	4	1
		Mikhail Kukushkin	6	6
									Mikhail Kukushkin	4	79	64
								7	Steve Johnson	6	67	77
	Q	Tristan Schoolkate	4	2
	7	Steve Johnson	6	6

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	J Duckworth	77	7
		B Zhukayev	62	5				1	J Duckworth	4	6	4
		T Sandgren	4	6	77				T Sandgren	6	3	6
		M Krueger	6	1	65											T Sandgren	7	6
	Q	M Sasikumar	7	4	77										Q	M Sasikumar	5	4
	WC	E Quinn	5	6	64			Q	M Sasikumar	4	6	7
		E Spizzirri	63	3				5	A Galarneau	6	2	5
	5	A Galarneau	77	6																			T Sandgren	4	1
	3	D Kudla	6	5	6																		M Kukushkin	6	6
	Alt	S Mansouri	3	7	3			3	D Kudla	6	3	6
	WC	K Nishikori	6	6				WC	K Nishikori	4	6	3
		A Walton	1	2											3	D Kudla	4	1
	PR	C Harrison	2	79	65											M Kukushkin	6	6
		M Kukushkin	6	67	77				M Kukushkin	3	6	6
		N Basavareddy	6	3	3			6	G Mpetshi Perricard	6	3	2
	6	G Mpetshi Perricard	3	6	6

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	8	D Sweeny	5	1
	Q	O Jasika	7	6				Q	O Jasika	6	6
		Y Shimizu	77	4	6				Y Shimizu	3	3
	Q	E Escobedo	65	6	3										Q	O Jasika	4	3
	Q	E Zhu	77	2	4										Q	T Schoolkate	6	6
	Q	T Schoolkate	60	6	6			Q	T Schoolkate	77	7
		M Lajal	77	4	4			4	A Çelikbilek	64	5
	4	A Çelikbilek	63	6	6																	Q	T Schoolkate	4	2
	7	S Johnson	79	6																		7	S Johnson	6	6
	Q	A McHugh	67	4				7	S Johnson	6	6
	Alt	J McCabe	6	64	77			Alt	J McCabe	4	2
		A Shelbayh	3	77	65										7	S Johnson	6	60	77
		Y Uchiyama	6	6												Y Uchiyama	4	77	64
		L Tu	1	3					Y Uchiyama	6	6
	WC	Michael Zheng	4	1				2	E Gómez	2	4
	2	E Gómez	6	6

References

External links

• Main draw
• Qualifying draw