1989 Atlantic 10 Conference
baseball tournament
Teams4
FormatFour-team double elimination
Finals site
ChampionsGeorge Washington (2nd title)
Winning coachJohn Castleberry (1st title)
MVPMike Palys/Frank Terry (Temple/George Washington)

The 1989 Atlantic 10 Conference Baseball Championship was held at Bear Stadium in Boyertown, Pennsylvania from May 12 through 14. The double elimination tournament featured the top two regular-season finishers from both of the league's divisions. West top seed George Washington defeated Temple in the title game to win the tournament for the second time, earning the Atlantic 10's automatic bid to the 1989 NCAA tournament.[1]

Seeding and format

Each division's top teams, based on winning percentage in the 16-game regular season schedule, qualified for the field. In the opening round of the four-team double-elimination format, the East Division champion played the West Division runner-up, and vice versa.

TeamWLPct.GBSeed
East Division
Rutgers142.875
–
1E
Temple115.688
3
2E
Rhode Island510.333
8.5
–
Massachusetts511.313
9
–
Saint Joseph's411.267
9.5
–
West Division
George Washington133.813
–
1W
Penn State124.750
1
2W
West Virginia95.643
3
–
St. Bonaventure410.286
8
–
Duquesne016.000
13
–

Bracket

First roundSemi-finalsFinals
1WGeorge Washington1
2ETemple10
2ETemple9
1ERutgers7
1ERutgers6
2WPenn State1
2ETemple28
1WGeorge Washington39
Lower round 1Lower final
1ERutgers3
1WGeorge Washington31WGeorge Washington6
2WPenn State2

All-Tournament

Temple's Mike Palys and George Washington's Frank Terry shared Most Valuable Player honors. George Washington's Mike Rolfes was named Most Valuable Pitcher.

References

  1. ↑ "2014 Atlantic 10 Baseball Record Book" (PDF). Atlantic10.com. Archived from the original (PDF) on May 19, 2014. Retrieved July 15, 2014.
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