1998 Tour de Hongrie
Race details
Dates23–30 August
Stages7 + Prologue
Distance1,078.5[1] km (670.1 mi)
Winning time27h 16' 24"
Results
Winner  Aleksandr Rotar (UKR) (Torov Kir)
  Second  Nazarenko (UKR) (Torov Kir)
  Third  Károly Eisenkrammer (HUN) (Postás-Matáv)
Points  Yuriy Krivtsov (UKR) (Torov Kir)
Mountains  Aleksandr Rotar (UKR) (Torov Kir)
  Team Torov Kir

The 1998 Tour de Hongrie was the 27th edition of the Tour de Hongrie cycle race and was held from 23 to 30 August 1998. The race started and finished in Budapest. The race was won by Aleksandr Rotar.

General classification

Final general classification[1][2]
Rank Rider Team Time
1  Aleksandr Rotar (UKR) Torov Kir 27h 16' 24"
2  Nazarenko (UKR) Torov Kir + 51"
3  Károly Eisenkrammer (HUN) Postás-Matáv + 1' 25"

References

  1. 1 2 "27. Tour de Hongrie: Minden az ukránoké (1998)". tdh.hu. Retrieved 22 July 2019.
  2. ↑ "1998 Tour de Hongrie". First Cycling. Retrieved 21 July 2019.
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