Battle of Palmar
Part of the Paraguayan War
DateSeptember 2, 1866
Location
Paraguay River, Paraguay
Result Brazilian victory
Belligerents
Commanders and leaders
Empire of Brazil Viscount of Porto Alegre Paraguay Unknown
Strength
+10,000 soldiers
10 warships		 Unknown
Casualties and losses
70 dead Unknown

The Battle of Palmar was a confrontation of the Paraguayan War between a squad of the Brazilian Armada and army troops against a group of Paraguayan soldiers on the Paraguay River, fought on September 2, 1866 and which resulted in victory for the allies.[1]

The Battle

Palmar was an island in the Paraguay River near the blockade station of the Brazilian fleet. On September 1, 1866, the 2nd Army Corps commanded by the Baron of Porto Alegre embarked on squadron ships to disembark close to the defensive lines of Curuzú. At dawn the next day, the battleship Tamandaré, the warships Forte de Coimbra and Pedro Afonso, three flatboats and the wooden ships Araguaia, Beberibe, Greenhalg, Ivaí, Ipiranga, Araguari and Parnaíba started a heavy bombardment of the island and its surroundings, sweeping the defenders Paraguayans who were there. At 3 pm troops from Porto Alegre disembarked on the island and started a fight with the remnants of the defenders losing 70 men, but they were successful in disembarking.[2]

References

  1. ↑ Hooker, Terry D. (2008). Armies of the nineteenth century. The Americas. Heath, Ian, 1952-. Nottingham, United Kingdom: Foundry Books. ISBN 978-1-901543-15-5. OCLC 429032555.
  2. ↑ Donato, Hernâni (1996). Dicionário das batalhas brasileiras (in Portuguese). São Paulo: Instituição Brasileira de Difusão Cultural. ISBN 978-85-348-0034-1. OCLC 36768251.

Bibliography

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