  Dint Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 69°17′S 71°49′W / 69.283°S 71.817°W |
| Length | 3 km (1.9 mi) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | Uninhabited |
Dint Island is a rocky island, 3 kilometres (1.5 nmi) long. Probably first seen from the air by the United States Antarctic Service, 1939–41, it was first mapped from air photos taken by the Ronne Antarctic Research Expedition, 1947–48, by D. Searle of the Falkland Islands Dependencies Survey in 1960. It was so named by the UK Antarctic Place-Names Committee because a distinctive cirque makes a dent, or dint, on the south side of the island.[1]
Location
Dint Island is located at (69°17′S 71°49′W / 69.283°S 71.817°W) and lies 4 kilometres (2 nmi) off the west side of Alexander Island within Lazarev Bay. The island lies roughly 6 miles (10 km) southeast of Umber Island.
See also
Further reading
- Defense Mapping Agency 1992, Sailing Directions (planning Guide) and (enroute) for Antarctica, P 379
External links
- Dint Island on USGS website
- Dint Island on SCAR website
- Dint Island on marineregions.org
- Dint Island distance calculator
References
- ↑ "Dint Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 21 January 2012.
This article incorporates public domain material from "Dint Island". Geographic Names Information System. United States Geological Survey.