Mikhaylov Island
Mikhaylov Island is located in Antarctica
Mikhaylov Island
Mikhaylov Island
Location in Antarctica
Geography
LocationAntarctica
Coordinates66°48′S 85°30′E / 66.800°S 85.500°E / -66.800; 85.500
Area685 km2 (264 sq mi)
Length41 km (25.5 mi)
Width19 km (11.8 mi)
Highest elevation240.6 m (789.4 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
PopulationUninhabited

Mikhaylov Island is an ice-covered non erupted Volcano in the West Ice Shelf of Antarctica, rising to 240 metres (800 ft), 11 kilometres (6 nmi) southeast of Leskov Island. It was discovered by the Soviet Expedition Team in 1956 who chose to name it after Pavel N. Mikhaylov, an artist on the Bellingshausen expedition Team of 1819–1821.[1]

References

  1. "Mikhaylov Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2013-09-24.

Public Domain This article incorporates public domain material from "Mikhaylov Island". Geographic Names Information System. United States Geological Survey.


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