General form with chemical activities

When an oxidizer (Ox) accepts a number z of electrons ( e⁻) to be converted in its reduced form (Red), the half-reaction is expressed as:

${\displaystyle {\ce {Ox + ze- -> Red}}}$

The reaction quotient (Q_r), also often called the ion activity product (IAP), is the ratio between the chemical activities (a) of the reduced form (the reductant, a_Red) and the oxidized form (the oxidant, a_Ox). The chemical activity of a dissolved species corresponds to its true thermodynamic concentration taking into account the electrical interactions between all ions present in solution at elevated concentrations. For a given dissolved species, its chemical activity (a) is the product of its activity coefficient (γ) by its molar (mol/L solution), or molal (mol/kg water), concentration (C): a = γ C. So, if the concentration (C, also denoted here below with square brackets [ ]) of all the dissolved species of interest are sufficiently low and that their activity coefficients are close to unity, their chemical activities can be approximated by their concentrations as commonly done when simplifying, or idealizing, a reaction for didactic purposes:

${\displaystyle Q_{r}={\frac {a_{\text{Red}}}{a_{\text{Ox}}}}={\frac {[\operatorname {Red} ]}{[\operatorname {Ox} ]}}}$

At chemical equilibrium, the ratio Q_r of the activity of the reaction product (a_Red) by the reagent activity (a_Ox) is equal to the equilibrium constant K of the half-reaction:

${\displaystyle K={\frac {a_{\text{Red}}}{a_{\text{Ox}}}}}$

The standard thermodynamics also says that the actual Gibbs free energy ΔG is related to the free energy change under standard state ΔG^o
by the relationship:

$${\displaystyle \Delta G=\Delta G^{\ominus }+RT\ln Q_{r}}$$

where Q_r is the reaction quotient and R is the universal ideal gas constant.

The cell potential E associated with the electrochemical reaction is defined as the decrease in Gibbs free energy per coulomb of charge transferred, which leads to the relationship

$${\displaystyle \Delta G=-zFE.}$$

The constant F (the Faraday constant) is a unit conversion factor F = N_Aq, where N_A is the Avogadro constant and q is the fundamental electron charge. This immediately leads to the Nernst equation, which for an electrochemical half-cell is

$${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\ln Q_{r}=E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\ln {\frac {a_{\text{Red}}}{a_{\text{Ox}}}}.}$$

For a complete electrochemical reaction (full cell), the equation can be written as

$${\displaystyle E_{\text{cell}}=E_{\text{cell}}^{\ominus }-{\frac {RT}{zF}}\ln Q_{r}}$$

where:

• E_red is the half-cell reduction potential at the temperature of interest,
• E^o
  _red is the standard half-cell reduction potential,
• E_cell is the cell potential (electromotive force) at the temperature of interest,
• E^o
  _cell is the standard cell potential,
• R is the universal ideal gas constant: R = 8.31446261815324 J K⁻¹ mol⁻¹,
• T is the temperature in kelvins,
• z is the number of electrons transferred in the cell reaction or half-reaction,
• F is the Faraday constant, the magnitude of charge (in coulombs) per mole of electrons: F = 96485.3321233100184 C mol⁻¹,
• Q_r is the reaction quotient of the cell reaction, and,
• a is the chemical activity for the relevant species, where a_Red is the activity of the reduced form and a_Ox is the activity of the oxidized form.

Thermal voltage

At room temperature (25 °C), the thermal voltage ${\displaystyle V_{T}={\frac {RT}{F}}}$ is approximately 25.693 mV. The Nernst equation is frequently expressed in terms of base-10 logarithms (i.e., common logarithms) rather than natural logarithms, in which case it is written:

$${\displaystyle E=E^{\ominus }-{\frac {V_{T}}{z}}\ln {\frac {a_{\text{Red}}}{a_{\text{Ox}}}}=E^{\ominus }-{\frac {\lambda V_{T}}{z}}\log _{10}{\frac {a_{\text{Red}}}{a_{\text{Ox}}}}.}$$

where λ = ln(10) ≈ 2.3026 and λV_T ≈ 0.05916 Volt.

Form with activity coefficients and concentrations

Similarly to equilibrium constants, activities are always measured with respect to the standard state (1 mol/L for solutes, 1 atm for gases, and T = 298.15 K, i.e., 25 °C or 77 °F). The chemical activity of a species i, a_i, is related to the measured concentration C_i via the relationship a_i = γ_i C_i, where γ_i is the activity coefficient of the species i. Because activity coefficients tend to unity at low concentrations, or are unknown or difficult to determine at medium and high concentrations, activities in the Nernst equation are frequently replaced by simple concentrations and then, formal standard reduction potentials ${\displaystyle E_{\text{red}}^{\ominus '}}$ used.

Taking into account the activity coefficients (${\displaystyle \gamma }$) the Nernst equation becomes:

$${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\ln \left({\frac {\gamma _{\text{Red}}}{\gamma _{\text{Ox}}}}{\frac {C_{\text{Red}}}{C_{\text{Ox}}}}\right)}$$

$${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\left(\ln {\frac {\gamma _{\text{Red}}}{\gamma _{\text{Ox}}}}+\ln {\frac {C_{\text{Red}}}{C_{\text{Ox}}}}\right)}$$

$${\displaystyle E_{\text{red}}=\underbrace {\left(E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\ln {\frac {\gamma _{\text{Red}}}{\gamma _{\text{Ox}}}}\right)} _{E_{\text{red}}^{\ominus '}}-{\frac {RT}{zF}}\ln {\frac {C_{\text{Red}}}{C_{\text{Ox}}}}}$$

Where the first term including the activity coefficients (${\displaystyle \gamma }$) is denoted ${\displaystyle E_{\text{red}}^{\ominus '}}$ and called the formal standard reduction potential, so that ${\displaystyle E_{\text{red}}}$ can be directly expressed as a function of ${\displaystyle E_{\text{red}}^{\ominus '}}$ and the concentrations in the simplest form of the Nernst equation:

$${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus '}-{\frac {RT}{zF}}\ln {\frac {C_{\text{Red}}}{C_{\text{Ox}}}}}$$

Formal standard reduction potential

When wishing to use simple concentrations in place of activities, but that the activity coefficients are far from unity and can no longer be neglected and are unknown or too difficult to determine, it can be convenient to introduce the notion of the "so-called" standard formal reduction potential (${\displaystyle E_{\text{red}}^{\ominus '}}$) which is related to the standard reduction potential as follows:^[3]

$${\displaystyle E_{\text{red}}^{\ominus '}=E_{\text{red}}^{\ominus }-{\frac {RT}{zF}}\ln {\frac {\gamma _{\text{Red}}}{\gamma _{\text{Ox}}}}}$$

So that the Nernst equation for the half-cell reaction can be correctly formally written in terms of concentrations as:

$${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus '}-{\frac {RT}{zF}}\ln {\frac {C_{\text{Red}}}{C_{\text{Ox}}}}}$$

and likewise for the full cell expression.

According to Wenzel (2020),^[4] a formal reduction potential ${\displaystyle E_{\text{red}}^{\ominus '}}$ is the reduction potential that applies to a half reaction under a set of specified conditions such as, e.g., pH, ionic strength, or the concentration of complexing agents.

The formal reduction potential ${\displaystyle E_{\text{red}}^{\ominus '}}$ is often a more convenient, but conditional, form of the standard reduction potential, taking into account activity coefficients and specific conditions characteristics of the reaction medium. Therefore, its value is a conditional value, i.e., that it depends on the experimental conditions and because the ionic strength affects the activity coefficients, ${\displaystyle E_{\text{red}}^{\ominus '}}$ will vary from medium to medium.^[3] Several definitions of the formal reduction potential can be found in the literature, depending on the pursued objective and the experimental constraints imposed by the studied system. The general definition of ${\displaystyle E_{\text{red}}^{\ominus '}}$ refers to its value determined when ${\displaystyle {\frac {C_{\text{red}}}{C_{\text{ox}}}}=1}$. A more particular case is when ${\displaystyle E_{\text{red}}^{\ominus '}}$ is also determined at pH 7, as e.g. for redox reactions important in biochemistry or biological systems.

Expression of the Nernst equation as a function of pH

The ${\displaystyle E_{h}}$ and pH of a solution are related by the Nernst equation as commonly represented by a Pourbaix diagram (${\displaystyle E_{h}}$ – pH plot). ${\displaystyle E_{h}}$ explicitly denotes ${\displaystyle E_{\text{red}}}$ expressed versus the standard hydrogen electrode (SHE). For a half cell equation, conventionally written as a reduction reaction (i.e., electrons accepted by an oxidant on the left side):

${\displaystyle a\,A+b\,B+h\,{\ce {H+}}+z\,e^{-}\quad {\ce {<=>}}\quad c\,C+d\,D}$

The half-cell standard reduction potential ${\displaystyle E_{\text{red}}^{\ominus }}$ is given by

${\displaystyle E_{\text{red}}^{\ominus }({\text{volt}})=-{\frac {\Delta G^{\ominus }}{zF}}}$

where ${\displaystyle \Delta G^{\ominus }}$ is the standard Gibbs free energy change, z is the number of electrons involved, and F is the Faraday's constant. The Nernst equation relates pH and ${\displaystyle E_{h}}$ as follows:

${\displaystyle E_{h}=E_{\text{red}}=E_{\text{red}}^{\ominus }-{\frac {0.05916}{z}}\log \left({\frac {\{C\}^{c}\{D\}^{d}}{\{A\}^{a}\{B\}^{b}}}\right)-{\frac {0.05916\,h}{z}}{\text{pH}}}$  

where curly brackets indicate activities, and exponents are shown in the conventional manner. This equation is the equation of a straight line for ${\displaystyle E_{\text{red}}}$ as a function of pH with a slope of ${\displaystyle -0.05916\,\left({\frac {h}{z}}\right)}$ volt (pH has no units).

This equation predicts lower ${\displaystyle E_{\text{red}}}$ at higher pH values. This is observed for the reduction of O₂ into H₂O, or OH⁻, and for the reduction of H⁺ into H₂. ${\displaystyle E_{\text{red}}}$ is then often noted as ${\displaystyle E_{h}}$ to indicate that it refers to the standard hydrogen electrode (SHE) whose ${\displaystyle E_{\text{red}}}$ = 0 by convention under standard conditions (T = 298.15 K = 25 °C = 77 F, P_gas = 1 atm (1.013 bar), concentrations = 1 M and thus pH = 0).

Examples with a Pourbaix diagram

Main article: Pourbaix diagram

Pourbaix diagram for water, including stability regions for water, oxygen and hydrogen at standard temperature and pressure (STP). The vertical scale (ordinate) is the electrode potential relative to a SHE electrode. The horizontal scale (abscissa) is the pH of the electrolyte (otherwise non-interacting). Above the top line oxygen will bubble off of the electrode until water is totally consumed. Likewise, below the bottom line hydrogen will bubble off of the electrode until water is totally consumed.

To illustrate the dependency of the reduction potential on pH, one can simply consider the two oxido-reduction equilibria determining the water stability domain in a Pourbaix diagram (E_h–pH plot). When water is submitted to electrolysis by applying a sufficient difference of electrical potential between two electrodes immersed in water, hydrogen is produced at the cathode (reduction of water protons) while oxygen is formed at the anode (oxidation of water oxygen atoms). The same may occur if a reductant stronger than hydrogen (e.g., metallic Na) or an oxidant stronger than oxygen (e.g., F₂) enters in contact with water and reacts with it. In the E_h–pH plot here beside (the simplest possible version of a Pourbaix diagram), the water stability domain (grey surface) is delimited in term of redox potential by two inclined red dashed lines:

• Lower stability line with hydrogen gas evolution due to the proton reduction at very low E_h:

2 H⁺ + 2 e⁻ ⇌ H₂ (cathode: reduction)

• Higher stability line with oxygen gas evolution due to water oxygen oxidation at very high E_h:

2 H₂O ⇌ O₂ + 4 H⁺ + 4 e⁻ (anode: oxidation)

When solving the Nernst equation for each corresponding reduction reaction (need to revert the water oxidation reaction producing oxygen), both equations have a similar form because the number of protons and the number of electrons involved within a reaction are the same and their ratio is one (2 H⁺/2 e⁻ for H₂ and 4 H⁺/4 e⁻ with O₂ respectively), so it simplifies when solving the Nernst equation expressed as a function of pH.

The result can be numerically expressed as follows:

${\displaystyle E_{\text{red}}=E_{\text{red}}^{\ominus }-0.05916\ pH}$

Note that the slopes of the two water stability domain upper and lower lines are the same (-59.16 mV/pH unit), so they are parallel on a Pourbaix diagram. As the slopes are negative, at high pH, both hydrogen and oxygen evolution requires a much lower reduction potential than at low pH.

For the reduction of H⁺ into H₂ the here above mentioned relationship becomes:

${\displaystyle E_{\text{red}}=-0.05916\ pH}$
because by convention ${\displaystyle E_{\text{red}}^{\ominus }}$ = 0 V for the standard hydrogen electrode (SHE: pH = 1).
So, at pH = 7, ${\displaystyle E_{\text{red}}}$ = -0.414 V for the reduction of protons.

For the reduction of O₂ into 2 H₂O the here above mentioned relationship becomes:

${\displaystyle E_{\text{red}}=1.229-0.05916\ pH}$
because ${\displaystyle E_{\text{red}}^{\ominus }}$ = +1.229 V with respect to the standard hydrogen electrode (SHE: pH = 1).
So, at pH = 7, ${\displaystyle E_{\text{red}}}$ = +0.815 V for the reduction of oxygen.

The offset of -414 mV in ${\displaystyle E_{\text{red}}}$ is the same for both reduction reactions because they share the same linear relationship as a function of pH and the slopes of their lines are the same. This can be directly verified on a Pourbaix diagram. For other reduction reactions, the value of the formal reduction potential at a pH of 7, commonly referred for biochemical reactions, also depends on the slope of the corresponding line in a Pourbaix diagram i.e. on the ratio h⁄z of the number of  H⁺ to the number of  e⁻ involved in the reduction reaction, and thus on the stoichiometry of the half-reaction. The determination of the formal reduction potential at pH = 7 for a given biochemical half-reaction requires thus to calculate it with the corresponding Nernst equation as a function of pH. One cannot simply apply an offset of -414 mV to the E_h value (SHE) when the ratio h⁄z differs from 1.

Nernst potential

The Nernst equation has a physiological application when used to calculate the potential of an ion of charge z across a membrane. This potential is determined using the concentration of the ion both inside and outside the cell:

$${\displaystyle E={\frac {RT}{zF}}\ln {\frac {[{\text{ion outside cell}}]}{[{\text{ion inside cell}}]}}=2.3026{\frac {RT}{zF}}\log _{10}{\frac {[{\text{ion outside cell}}]}{[{\text{ion inside cell}}]}}.}$$

When the membrane is in thermodynamic equilibrium (i.e., no net flux of ions), and if the cell is permeable to only one ion, then the membrane potential must be equal to the Nernst potential for that ion.

Goldman equation

When the membrane is permeable to more than one ion, as is inevitably the case, the resting potential can be determined from the Goldman equation, which is a solution of G-H-K influx equation under the constraints that total current density driven by electrochemical force is zero:

$${\displaystyle E_{\mathrm {m} }={\frac {RT}{F}}\ln {\left({\frac {\displaystyle \sum _{i}^{N}P_{\mathrm {M} _{i}^{+}}\left[\mathrm {M} _{i}^{+}\right]_{\mathrm {out} }+\displaystyle \sum _{j}^{M}P_{\mathrm {A} _{j}^{-}}\left[\mathrm {A} _{j}^{-}\right]_{\mathrm {in} }}{\displaystyle \sum _{i}^{N}P_{\mathrm {M} _{i}^{+}}\left[\mathrm {M} _{i}^{+}\right]_{\mathrm {in} }+\displaystyle \sum _{j}^{M}P_{\mathrm {A} _{j}^{-}}\left[\mathrm {A} _{j}^{-}\right]_{\mathrm {out} }}}\right)},}$$

where

• E_m is the membrane potential (in volts, equivalent to joules per coulomb),
• P_ion is the permeability for that ion (in meters per second),
• [ion]_out is the extracellular concentration of that ion (in moles per cubic meter, to match the other SI units, though the units strictly don't matter, as the ion concentration terms become a dimensionless ratio),
• [ion]_in is the intracellular concentration of that ion (in moles per cubic meter),
• R is the ideal gas constant (joules per kelvin per mole),
• T is the temperature in kelvins,
• F is the Faraday's constant (coulombs per mole).

The potential across the cell membrane that exactly opposes net diffusion of a particular ion through the membrane is called the Nernst potential for that ion. As seen above, the magnitude of the Nernst potential is determined by the ratio of the concentrations of that specific ion on the two sides of the membrane. The greater this ratio the greater the tendency for the ion to diffuse in one direction, and therefore the greater the Nernst potential required to prevent the diffusion. A similar expression exists that includes r (the absolute value of the transport ratio). This takes transporters with unequal exchanges into account. See: sodium-potassium pump where the transport ratio would be 2/3, so r equals 1.5 in the formula below. The reason why we insert a factor r = 1.5 here is that current density by electrochemical force J_e.c.(Na⁺) + J_e.c.(K⁺) is no longer zero, but rather J_e.c.(Na⁺) + 1.5J_e.c.(K⁺) = 0 (as for both ions flux by electrochemical force is compensated by that by the pump, i.e. J_e.c. = −J_pump), altering the constraints for applying GHK equation. The other variables are the same as above. The following example includes two ions: potassium (K⁺) and sodium (Na⁺). Chloride is assumed to be in equilibrium.

$${\displaystyle E_{m}={\frac {RT}{F}}\ln {\left({\frac {rP_{\mathrm {K} ^{+}}\left[\mathrm {K} ^{+}\right]_{\mathrm {out} }+P_{\mathrm {Na} ^{+}}\left[\mathrm {Na} ^{+}\right]_{\mathrm {out} }}{rP_{\mathrm {K} ^{+}}\left[\mathrm {K} ^{+}\right]_{\mathrm {in} }+P_{\mathrm {Na} ^{+}}\left[\mathrm {Na} ^{+}\right]_{\mathrm {in} }}}\right)}.}$$

When chloride (Cl⁻) is taken into account,

$${\displaystyle E_{m}={\frac {RT}{F}}\ln {\left({\frac {rP_{\mathrm {K} ^{+}}\left[\mathrm {K} ^{+}\right]_{\mathrm {out} }+P_{\mathrm {Na} ^{+}}\left[\mathrm {Na} ^{+}\right]_{\mathrm {out} }+P_{\mathrm {Cl} ^{-}}\left[\mathrm {Cl} ^{-}\right]_{\mathrm {in} }}{rP_{\mathrm {K} ^{+}}\left[\mathrm {K} ^{+}\right]_{\mathrm {in} }+P_{\mathrm {Na} ^{+}}\left[\mathrm {Na} ^{+}\right]_{\mathrm {in} }+P_{\mathrm {Cl} ^{-}}\left[\mathrm {Cl} ^{-}\right]_{\mathrm {out} }}}\right)}.}$$

Using Boltzmann factor

For simplicity, we will consider a solution of redox-active molecules that undergo a one-electron reversible reaction

Ox + e⁻ ⇌ Red

and that have a standard potential of zero, and in which the activities are well represented by the concentrations (i.e. unit activity coefficient). The chemical potential μ_c of this solution is the difference between the energy barriers for taking electrons from and for giving electrons to the working electrode that is setting the solution's electrochemical potential. The ratio of oxidized to reduced molecules, [Ox]/[Red], is equivalent to the probability of being oxidized (giving electrons) over the probability of being reduced (taking electrons), which we can write in terms of the Boltzmann factor for these processes:

$${\displaystyle {\begin{aligned}{\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}&={\frac {\exp \left(-[{\text{barrier for gaining an electron}}]/kT\right)}{\exp \left(-[{\text{barrier for losing an electron}}]/kT\right)}}\\[6px]&=\exp \left({\frac {\mu _{\mathrm {c} }}{kT}}\right).\end{aligned}}}$$

Taking the natural logarithm of both sides gives

$${\displaystyle \mu _{\mathrm {c} }=kT\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}.}$$

If μ_c ≠ 0 at [Ox]/[Red] = 1, we need to add in this additional constant:

$${\displaystyle \mu _{\mathrm {c} }=\mu _{\mathrm {c} }^{\ominus }+kT\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}.}$$

Dividing the equation by e to convert from chemical potentials to electrode potentials, and remembering that k/e = R/F,^[11] we obtain the Nernst equation for the one-electron process Ox + e⁻ ⇌ Red :

$${\displaystyle {\begin{aligned}E&=E^{\ominus }-{\frac {kT}{e}}\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}\\&=E^{\ominus }-{\frac {RT}{F}}\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}.\end{aligned}}}$$

Using thermodynamics (chemical potential)

Quantities here are given per molecule, not per mole, and so Boltzmann constant k and the electron charge e are used instead of the gas constant R and Faraday's constant F. To convert to the molar quantities given in most chemistry textbooks, it is simply necessary to multiply by the Avogadro constant: R = kN_A and F = eN_A. The entropy of a molecule is defined as

$${\displaystyle S\ {\stackrel {\mathrm {def} }{=}}\ k\ln \Omega ,}$$

where Ω is the number of states available to the molecule. The number of states must vary linearly with the volume V of the system (here an idealized system is considered for better understanding, so that activities are posited very close to the true concentrations. Fundamental statistical proof of the mentioned linearity goes beyond the scope of this section, but to see this is true it is simpler to consider usual isothermal process for an ideal gas where the change of entropy ΔS = nR ln(V₂/V₁) takes place. It follows from the definition of entropy and from the condition of constant temperature and quantity of gas n that the change in the number of states must be proportional to the relative change in volume V₂/V₁. In this sense there is no difference in statistical properties of ideal gas atoms compared with the dissolved species of a solution with activity coefficients equaling one: particles freely "hang around" filling the provided volume), which is inversely proportional to the concentration c, so we can also write the entropy as

$${\displaystyle S=k\ln \ (\mathrm {constant} \times V)=-k\ln \ (\mathrm {constant} \times c).}$$

The change in entropy from some state 1 to another state 2 is therefore

$${\displaystyle \Delta S=S_{2}-S_{1}=-k\ln {\frac {c_{2}}{c_{1}}},}$$

so that the entropy of state 2 is

$${\displaystyle S_{2}=S_{1}-k\ln {\frac {c_{2}}{c_{1}}}.}$$

If state 1 is at standard conditions, in which c₁ is unity (e.g., 1 atm or 1 M), it will merely cancel the units of c₂. We can, therefore, write the entropy of an arbitrary molecule A as

$${\displaystyle S(\mathrm {A} )=S^{\ominus }(\mathrm {A} )-k\ln[\mathrm {A} ],}$$

where ${\displaystyle S^{\ominus }}$ is the entropy at standard conditions and [A] denotes the concentration of A. The change in entropy for a reaction

is then given by

$${\displaystyle \Delta S_{\mathrm {rxn} }={\big (}yS(\mathrm {Y} )+zS(\mathrm {Z} ){\big )}-{\big (}aS(\mathrm {A} )+bS(\mathrm {B} ){\big )}=\Delta S_{\mathrm {rxn} }^{\ominus }-k\ln {\frac {[\mathrm {Y} ]^{y}[\mathrm {Z} ]^{z}}{[\mathrm {A} ]^{a}[\mathrm {B} ]^{b}}}.}$$

We define the ratio in the last term as the reaction quotient:

$${\displaystyle Q_{r}={\frac {\displaystyle \prod _{j}a_{j}^{\nu _{j}}}{\displaystyle \prod _{i}a_{i}^{\nu _{i}}}}\approx {\frac {[\mathrm {Z} ]^{z}[\mathrm {Y} ]^{y}}{[\mathrm {A} ]^{a}[\mathrm {B} ]^{b}}},}$$

where the numerator is a product of reaction product activities, aj, each raised to the power of a stoichiometric coefficient, νj, and the denominator is a similar product of reactant activities. All activities refer to a time t. Under certain circumstances (see chemical equilibrium) each activity term such as aνj
j may be replaced by a concentration term, [A].In an electrochemical cell, the cell potential E is the chemical potential available from redox reactions (E = μc/e). E is related to the Gibbs free energy change ΔG only by a constant: ΔG = −zFE, where n is the number of electrons transferred and F is the Faraday constant. There is a negative sign because a spontaneous reaction has a negative Gibbs free energy ΔG and a positive potential E. The Gibbs free energy is related to the entropy by G = H − TS, where H is the enthalpy and T is the temperature of the system. Using these relations, we can now write the change in Gibbs free energy,

$${\displaystyle \Delta G=\Delta H-T\Delta S=\Delta G^{\ominus }+kT\ln Q_{r},}$$

and the cell potential,

$${\displaystyle E=E^{\ominus }-{\frac {kT}{ze}}\ln Q_{r}.}$$

This is the more general form of the Nernst equation.

For the redox reaction Ox + z e⁻ → Red,

$${\displaystyle Q_{r}={\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}},}$$

and we have:

$${\displaystyle {\begin{aligned}E&=E^{\ominus }-{\frac {kT}{ze}}\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}\\&=E^{\ominus }-{\frac {RT}{zF}}\ln {\frac {[\mathrm {Red} ]}{[\mathrm {Ox} ]}}\\&=E^{\ominus }-{\frac {RT}{zF}}\ln Q_{r}.\end{aligned}}}$$

The cell potential at standard temperature and pressure (STP) ${\displaystyle E^{\ominus }}$ is often replaced by the formal potential ${\displaystyle E^{\ominus '}}$, which includes the activity coefficients of the dissolved species under given experimental conditions (T, P, ionic strength, pH, and complexing agents) and is the potential that is actually measured in an electrochemical cell.

Time dependence of the potential

The expression of time dependence has been established by Karaoglanoff.^{[14][15][16][17]}