1828 United States presidential election in Georgia

October 31 – December 2, 1828
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 9 0
Popular vote 19,362 642
Percentage 96.79% 3.21%

In the 1828 United States presidential election, Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.

Seven Georgian electors voted for William Smith for vice president, rather than Jackson's official running mate, John C. Calhoun.[1]

Results

United States presidential election in Georgia, 1828[2]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 19,362 96.79% 9
National Republican John Quincy Adams (incumbent) 642 3.21% 0
Totals 20,004 100.0% 9

References

  1. "Electoral Votes for President and Vice President, 1821-1837 – 1828 Election for the Eleventh Term". National Archives and Records Administration. Retrieved September 6, 2018.
  2. "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved February 28, 2013.
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