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Elections in Georgia |
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In the 1828 United States presidential election, Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.
Seven Georgian electors voted for William Smith for vice president, rather than Jackson's official running mate, John C. Calhoun.[1]
Results
United States presidential election in Georgia, 1828[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 19,362 | 96.79% | 9 | |
National Republican | John Quincy Adams (incumbent) | 642 | 3.21% | 0 | |
Totals | 20,004 | 100.0% | 9 | ||
References
- ↑ "Electoral Votes for President and Vice President, 1821-1837 – 1828 Election for the Eleventh Term". National Archives and Records Administration. Retrieved September 6, 2018.
- ↑ "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved February 28, 2013.
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