1836 United States presidential election in Georgia

November 3 – December 7, 1836
 
Nominee Hugh White Martin Van Buren
Party Whig Democratic
Home state Tennessee New York
Running mate John Tyler Richard Johnson
Electoral vote 11 0
Popular vote 24,481 22,778
Percentage 51.80% 48.20%

The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Georgia voted for Whig candidate Hugh White over the Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.

This was the only election in which a Democrat won the presidency without carrying Georgia until 1964, nearly 130 years later. Alongside Lyndon Johnson in that year, only Bill Clinton in 1996 (though he carried the state four years prior) and Barack Obama in 2008 and 2012 have been elected without carrying it.[1]

Results

United States presidential election in Georgia, 1836[2]
Party Candidate Votes Percentage Electoral votes
Whig Hugh White 24,481 51.80% 11
Democratic Martin Van Buren 22,778 48.20% 0
Totals 47,259 100.0% 11

References

  1. "Historical U.S. Presidential Elections 1789-2020". 270toWin.com. Retrieved December 25, 2021.
  2. "1836 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved August 4, 2012.


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.